Physics Work, Energy, Power and Collision NTA Abhiyas Question - Center of Mass and Momentum Conservation (Collision) MCQ (Single Correct)

A block A of mass m is in equilibrium after being suspended from the ceiling with the help of a spring of force constant k. The block B of mass m, strikes the block A with a speed v and sticks to it. The value of v for which the spring just attains its natural length is

A
B
C
D

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The correct answer is:
A

( a ) Let the velocity of the combined system just after the collision is v’ then using conservation of linear momentum we get

mv = 2mv’,

Now, using the conservation of mechanical energy we get

Initial elongation of the spring is

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